X=-42x^2=

Solution for X=-42x^2= equation:

X=-42X^2=

We move all terms to the left:

X-(-42X^2)=0

We get rid of parentheses

42X^2+X=0

a = 42; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·42·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*42}=\frac{-2}{84}
=-1/42
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*42}=\frac{0}{84}
=0
$